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An equiconvex lens is prepared from a glass of refractive index 1.5. The radius of curvature of the surface is 0.5 m. The focal length of the lens is-

1)0.5 m

2)1.0 m

3)1.5 m

4)2.0 m


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    0.5 m

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  • Exam: Light QUESTIONS





    1/f=(1.5-1)(1/0.5+1/0.5)
    = (0.5)(2+2)
    = 2
    f= 1/2=0.5m

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